## Remove TWO from FIVE

Wordplay: Remove TWO from FIVE and get FOUR.

**SOLUTION**

Remove TWO letters, “F” and “E”, from the word “FIVE” and get “IV” which is FOUR in Roman numerals.

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Wordplay: Remove TWO from FIVE and get FOUR.

Remove TWO letters, “F” and “E”, from the word “FIVE” and get “IV” which is FOUR in Roman numerals.

I am white when I am dirty, and black when I am clean. What am I?

The answer is BLACKBOARD.

A man is lying dead in a field. Next to him, there is an unopened package. There are no other people or animals in the field. How did he die?

The man was sky diving and his parachute did not open.

Take a square (or circle) coaster. Then, cut a hole in a piece of paper with the shape of a square, so that the side of that square is half of the side (or the diameter) of the coaster. Now, your goal is to push the coaster through the hole without tearing the paper (you can fold it).

Coming soon.

A hungry lion runs inside a circus arena which is a circle of radius 10 meters. Running in broken lines (i.e. along a piecewise linear trajectory), the lion covers 30 kilometers. Prove that the sum of all turning angles is at least 2998 radians.

Imagine the lion is static, facing North, and instead, the center of the arena moves around. Then, each time the lion runs X meters in some direction, this translates into the center moving X meters South. Each time the lion makes a turn of Y radians, this translates into the center moving along an arc of Y radians.

Thus, the problem translates to a point inside the arena alternating between traveling straight South and then moving along arcs around the center of the arena. Since the total distance traveled straight South by the point is 30KM and the distance between the starting and the ending points is at most 20M, the total distance traveled North must be at least 30KM – 20M = 29980M. Therefore, the total length of the arcs traversed by the point is at least 29980M, and since the radius of each arc is at most 10M, the total angle of the arcs must be at least 2998 radians. The sum of all turning angles of the lion is the same, so this concludes the proof.

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