# Rhombuses

A regular hexagon is split into small equilateral triangles and then the triangles are paired arbitrarily into rhombuses. Show that this results into three types of rhombuses based on orientation, with equal number of rhombuses from each type.

Color the rhombuses based on their type and imagine the diagram represents a structure of small cubes arranged in a larger cube. If you look at the large cube from three different angles, you will see exactly the three types of rhombuses on the diagram.

Alternatively, the problem can be proven more rigorously by considering the three sets of non-intersecting broken lines connecting the pairs of opposite sides of the hexagon, as shown on the image below. The type of each rhombus is determined by the types of the broken lines passing through it. Therefore, there are n² rhombuses of each type, where n is the length of the hexagon’s sides.

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#### Responses

1. The correct formula is n(3n-1)

1. Hi Không. What is this formula for? The number of rhombuses should by n^2; 25 on the picture above.

2. Ahhh sorry. I didn’t notice the bold lines so I calculate all rhombuses that could be formed. The problem doesn’t mentioned the bold lines