Symmetry and Perplexion

Find an X > 1, such that:

If we pick X=√2, (using a somewhat ambiguous notation) we get:

To see that the equality above holds, simply note that 2=(√2)² and take √2 root of both sides.

+ posts

We do not know where this puzzle originated from. If you have any information, please let us know via email.

Subscribe
Notify of
guest
0 Comments
Inline Feedbacks
View All Comments