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Viewing 41 - 51 of 51 posts
  • Vivek

    Member
    October 23, 2020 at 8:20 pm

    Got it!

  • Vivek

    Member
    October 22, 2020 at 2:42 am

    Another interesting question with the interesting answer as well! What is the expected number of throws till somebody wins?

  • Vivek

    Member
    October 22, 2020 at 1:57 am

    It really is (n/(n+1))^n for n sided dice, approximating to 1/e as n increases. Confirmed it by simulating in R program. This is the nice way to see the e value with probabilistic simulation. I remember that the probability of derangement approaches 1/e. But This one is really super cool!

  • Vivek

    Member
    October 21, 2020 at 4:11 am

    Oops made a mistake…it is 1/3 right? Not 1/6.

  • Vivek

    Member
    October 15, 2020 at 6:15 pm

    Wow interesting…reading about optional stopping theorem…

Viewing 41 - 51 of 51 posts