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White to play and mate Black in 20 moves.
The moves are as follows:
Can you add all 16 black pieces on the board (king, queen, 2 knights, 2 bishops, 2 rooks, 8 pawns) and get a chess position, in which no piece is attacked by another?
Yes, you can, as shown in the diagram below.
White to play and force the black king to d3.
1. Qc3+ Ka2 2. Qc1 Kb3 3. Qa1 Kc2 4. Qa2+ Kc3 5. Qb1 Kd2 6. Qb2+ Kd1 7. Qa2 Kc1 8. Qb3 Kd2 9. Qb1 Kc3 10. Qa2 Kd3
If 4. … Kc1, then 5. Qb3 and we get to the position in move 8. If 4. … Kd1, then 5. Qb1 Kd2 6. Qb2+ and we get to the position in move 6.
White starts with e2-e4 and the game finishes with Knight takes Rook mate in the fifth move. Recreate the game.
The game proceeds as follows:
1.e2-e4 Ng8-f6
2.Qd1-e2 Nf6xe4
3.f2-f3 Nd4-g3
4.Qe2xe7 Qd8xe7
5.Ke1-f2 Ng3xh1#
White to move and mate in 6. Can you tell what is so unusual about this puzzle?
What is so unusual about this puzzle is that there is only one possible income of the game. The moves are as follows:
The first four moves played by White are 1. f3, 2. Kf2, 3. Kg3, 4. Kh4. If White gets mated in the fourth move, what could be the moves played by Black?
The game proceeds as follows:
1. f3 e5 (or e6)
2. Kf2 Qf6
3. Kg3 Qxf3+
4. Kh4 Be7#
What is the smallest number of moves needed to result in this unusual position?
The shortest game takes just 4 moves:
1. Nf3 e5
2. Nxe5 Ne7
3. Nxd7 Nec6
4. Nxb8 Nxb8
Which is the best move for White in this position?
The best move is 1. Rc8+. Then either 1. … Kxb7 2. Rxd8, or 1. … Rxc8 2. Qxa7 Kxa7 3. bxc8 = N+, and Black loses both the Rook and the Queen.
Can you design a chess game that ends up with a stalemate in the 10th move?
One possible game is:
1. h4 h5
2. c4 a5
3. Qa4 Ra6
4. Qxa5 Rah6
5. Qxc7 f6
6. Qxd7 Kf7
7. Qxb7 Qd3
8. Qxb8 Qh7
9. Qxc8 Kg6
10. Qe6
White starts and forces Black to mate him in 8 moves.
1. Nb1+ Kb3
2. Qd1+ Rc23
3. Bc1 axb6
4. Ra1 b5
5. Rh1 bxc4
6. Ke1 c3
7. Ng1 f3
8. Bf1 f2#
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